Check the Divisibility by 2:
The number will be divided by 2 easily if it is even number (unit digit is 2,4,6,8,0)
Example: 123456, 1234, 4578 are divisible by 2 because a number is even and it ends with 2,4,6,8,0.
Check the Divisibility by 3:
The number will be easily divisible by 3 if its sum of the digit is divisible by 3.
Example: 729
For checking divisibility of 729 we must add 7+2+9=18 which is also divisible by 3. So
So 729 will be divisible by 3.
Check the Divisibility with 4:
In order to check divisibility with 4, you have to only see the number’s last two digits, if last two digits of the number are divisible by 4 then you can easily say that your number will be completely divisible by 4.
Example: 7985783324
The given number is very big. If We have to check its divisibility then we have to see only its last twodigit. i.e. 24 which comes in a table of 4
So we can easily say just by saying the number is divisible by 4
Check the Divisibility with 5:
It is very simple just by seeing the number you can tell the answer to it. If the last digit is either 0 or 5 the number will be completely divided by 5
Check the Divisibility by 6:
As we know
6=3*2
So in order to check divisibility with 6 it must have a factor of 2 and 3. We can say that the number will be divisible by both 2 and 3
So if the number is even it is divisible by 2 and if it’s some of the digits is divisible by 3 then it is divisible by 3
Hence after checking it’s divisibility by 2&3 we can say that no is divisible by 3
Example: 216
The given no is even no so and its some of the digits is 9 which comes in the table of 3 so no is also divisible by 3. Hence we can say that no will be divisible by 6 also.
Check the Divisibility with 7:
We use oscillator (– 2) for divisibility test.
for example take number 39732
step 1 : Separate unit place from the given number and multiplied by “2” for unit digit place ( 2 x 2 = 4) . This product is to be add for remaining number [ 3973 + (4) = 3969].
step 2 : Separate unit place from 3969 and multiplied by “2” for unit digit place ( 9 x 2 = 18) . This product is to be add for remaining number [ 396 + (18) = 378].
step 3 : Separate unit place from 378 and multiplied by “2” for unit digit place ( 8 x 2 = 16) . This product is to be add for remaining number [ 37 + (16) = 21].
Here 21 is divisible by 7 so the given number is also divisible by 7
Check the Divisibility with 8:
A number is divisible by 8, if the number formed with its last three digits is divisible by 8.
Example: Take number 24344. Consider the last two digits i.e. 344. As 344 is divisible by 8, the original number 24344 is also divisible by 8.
Check the Divisibility with 9:
A number is divisible by 9, ifsum of digits of a number are divisible by 9
Example: Consider 78532, as the sum of its digits (7+8+5+3+2) is 25, which is not divisible by 9, hence 78532 is not divisible by 9
Check the Divisibility with 10:
Divisibility rule for 10 states that any number whose last digit is 0, is divisible by 10.
Example: 10, 20,30,1000,5000,60000 etc.
Divisor 
Divisibility condition 
Examples 
1 
No special condition. Any integer is divisible by 1. 
2,3 etc 
2 
The last digit is even (0, 2, 4, 6, or 8) 
1,294: 4 is even. 
3 
sum of whose digits are divisible by 3 
516 = 5+1+6=12,which is divisible by 3. 
4 
If last two digits of number is divisible by 4. 
40,832: 32 is divisible by 4. 
5 
The last digit is 0 or 5 
405: the last digit is 5. 
6 
It is divisible by 2 and by 3. 
1458: 1 + 4 + 5 + 8 = 18, so it is divisible by 3 and the last digit is even, hence the number is divisible by 6. 
7 
Form the alternating sum of blocks of three from right to left. 
1,369,851: 851 − 369 + 1 = 483 = 7 × 69 
Subtract 2 times the last digit from the rest. (Works because 21 is divisible by 7.) 
483: 48 − (3 × 2) = 42 = 7 × 6. 

Or, add 5 times the last digit to the rest. (Works because 49 is divisible by 7.) 
483: 48 + (3 × 5) = 63 = 7 × 9. 

Or, add 3 times the first digit to the next. (This works because 10a + b − 7a = 3a + b − last number has the same remainder) 
483: 4×3 + 8 = 20 remainder 6, 6×3 + 3 = 21. 

8 
If last three digits of number is divisible by 8. 
413984 = 984/8 = 123 , which is divisible by 8 
9 
sum of digits of a number are divisible by 9. 
2,880: 2 + 8 + 8 + 0 = 18: 1 + 8 = 9, which is divisible by 9 
10 
The last digit is 0 
120: the last digit is 0. 
I hope, this article will help you a lot to understand the Divisibility Rules  Check the divisibility of number (1 – 10). If you still have any doubts and problems with any topic of mathematics you can ask your problem in the Ask Question section. You will get a reply shortly.
very..
very..easy..tricks..
seriously .
thanks sirr,,,
ANURESH..